The complete lecture — hydrocarbons come alive in the live panel as you read. Scroll down; the animation keeps pace as bromine water decolourises across a C=C and benzene's electrons circulate.
Alkanes are saturated and fairly unreactive; in sunlight a halogen substitutes an H by this three-stage radical chain.
The π electrons of the C=C attract electrophiles. With orange bromine water the colour disappears as the two Br atoms add to the carbons — the classic test for a double bond. Alkenes also add H₂ (Ni), HX and H₂O.
The H adds to the doubly-bonded carbon that already has the most hydrogens. Reason: this forms the more stable (secondary) carbocation, so Br⁻ ends up on the middle carbon.
| Reaction | Result |
|---|---|
| cold KMnO₄ | diol (purple fades) |
| O₃ then Zn/H₂O | two carbonyls (locates C=C) |
| n CH₂=CH₂ | –(CH₂CH₂)ₙ– polythene |
The H on a triple-bonded carbon is weakly acidic — terminal alkynes give a white silver-acetylide ppt with ammoniacal AgNO₃.
This delocalisation stabilises benzene, so it resists addition (which would break the ring) and prefers substitution.
| Reaction | Electrophile | Product |
|---|---|---|
| Nitration | NO₂⁺ | nitrobenzene |
| Halogenation | Cl⁺ (AlCl₃) | chlorobenzene |
| Sulphonation | SO₃ | benzenesulphonic acid |
| Friedel–Crafts | R⁺ / RCO⁺ | alkyl/aryl ketone |