Board-style MCQs and past-paper numericals in the Sindh Board (BIEK) pattern. Tap an option to check yourself instantly. Solved numericals are at the bottom.
Multiple-choice questions
Solved numericals & self-assessment (past papers)
Car accelerating from rest — distance in 6 s
A car starts from rest and accelerates at 2 m/s² for 6 s.
u = 0, a = 2 m/s², t = 6 s
S = ut + ½at² = 0 + ½(2)(6²) = ½(2)(36) = 36 m
Braking train — final velocity
A train moving at 15 m/s applies brakes giving a = −3 m/s² for 4 s.
v = u + at = 15 + (−3)(4) = 15 − 12 = 3 m/s
Stone dropped from a tower — speed & height after 3 s (g = 10)
u = 0, t = 3 s, g = 10 m/s²
v = u + gt = 0 + 10(3) = 30 m/s
h = ut + ½gt² = 0 + ½(10)(3²) = 45 m
Ball thrown straight up at 20 m/s — maximum height (g = 10)
At the highest point v = 0. Taking up as positive, a = −g.
2(−g)h = v² − u² → −20h = 0 − 400
h = 400 / 20 = 20 m
Projectile launched at 20 m/s, 30° — range & time of flight (g = 10)
u = 20 m/s, θ = 30°, g = 10
Time of flight T = 2u sinθ / g = 2(20)(0.5)/10 = 2 s
Range R = u² sin2θ / g = (400 × sin60°)/10 = (400 × 0.866)/10 = 34.6 m
Velocity–time graph — distance from the area
A body accelerates uniformly from rest to 20 m/s in 10 s.
distance = area under v–t line = ½ × base × height
= ½ × 10 × 20 = 100 m; acceleration = slope = 20/10 = 2 m/s²